x^2-0.7*x-0.3=0

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Solution for x^2-0.7*x-0.3=0 equation: 


Simplifying
x2 + -0.7x + -0.3 = 0

Reorder the terms:
-0.3 + -0.7x + x2 = 0

Solving
-0.3 + -0.7x + x2 = 0

Solving for variable 'x'.

Begin completing the square.

Move the constant term to the right:

Add '0.3' to each side of the equation.
-0.3 + -0.7x + 0.3 + x2 = 0 + 0.3

Reorder the terms:
-0.3 + 0.3 + -0.7x + x2 = 0 + 0.3

Combine like terms: -0.3 + 0.3 = 0.0
0.0 + -0.7x + x2 = 0 + 0.3
-0.7x + x2 = 0 + 0.3

Combine like terms: 0 + 0.3 = 0.3
-0.7x + x2 = 0.3

The x term is -0.7x.  Take half its coefficient (-0.35).
Square it (0.1225) and add it to both sides.

Add '0.1225' to each side of the equation.
-0.7x + 0.1225 + x2 = 0.3 + 0.1225

Reorder the terms:
0.1225 + -0.7x + x2 = 0.3 + 0.1225

Combine like terms: 0.3 + 0.1225 = 0.4225
0.1225 + -0.7x + x2 = 0.4225

Factor a perfect square on the left side:
(x + -0.35)(x + -0.35) = 0.4225

Calculate the square root of the right side: 0.65

Break this problem into two subproblems by setting 
(x + -0.35) equal to 0.65 and -0.65.


Subproblem 1
x + -0.35 = 0.65

Simplifying
x + -0.35 = 0.65

Reorder the terms:
-0.35 + x = 0.65

Solving
-0.35 + x = 0.65

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '0.35' to each side of the equation.
-0.35 + 0.35 + x = 0.65 + 0.35

Combine like terms: -0.35 + 0.35 = 0.00
0.00 + x = 0.65 + 0.35
x = 0.65 + 0.35

Combine like terms: 0.65 + 0.35 = 1
x = 1

Simplifying
x = 1


Subproblem 2
x + -0.35 = -0.65

Simplifying
x + -0.35 = -0.65

Reorder the terms:
-0.35 + x = -0.65

Solving
-0.35 + x = -0.65

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '0.35' to each side of the equation.
-0.35 + 0.35 + x = -0.65 + 0.35

Combine like terms: -0.35 + 0.35 = 0.00
0.00 + x = -0.65 + 0.35
x = -0.65 + 0.35

Combine like terms: -0.65 + 0.35 = -0.3
x = -0.3

Simplifying
x = -0.3


Solution
The solution to the problem is based on the solutions
from the subproblems.
x = {1, -0.3}

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